解析 JSON 数组并获取其中的第 n 个元素

本文介绍了解析 JSON 数组并获取其中特定元素的方法。给定一个 JSON 文本，其中包含一个名为“people”的数组，该数组包含多个人员对象，每个对象都有“craft”和“name”属性。目标是从该数组中获取第二个元素的“name”属性值。

我想解组 json 并从人员数组中获取第二个名字“andrey borisenko”，

json：

text = `{"people": [{"craft": "iss", "name": "sergey rizhikov"}, {"craft": "iss", "name": "andrey borisenko"}, {"craft": "iss", "name": "shane kimbrough"}, {"craft": "iss", "name": "oleg novitskiy"}, {"craft": "iss", "name": "thomas pesquet"}, {"craft": "iss", "name": "peggy whitson"}], "message": "success", "number": 6}`

到目前为止我的代码：

package main

import (
    "fmt"
    "encoding/json"
)


type people struct {
    NAME string `json:"craft"`
}

func main() {
    const text = `{"people": [{"craft": "ISS", "name": "Sergey Rizhikov"}, {"craft": "ISS", "name": "Andrey Borisenko"}, {"craft": "ISS", "name": "Shane Kimbrough"}, {"craft": "ISS", "name": "Oleg Novitskiy"}, {"craft": "ISS", "name": "Thomas Pesquet"}, {"craft": "ISS", "name": "Peggy Whitson"}], "message": "success", "number": 6}`
        textBytes := []byte(text)

    people1 := people{}
    err := json.Unmarshal(textBytes, &people1)
    if err != nil {
        fmt.Println(err)
        return
    }
    fmt.Println(people1.NAME.[1])
}

解决方案

您对 json.unmarshal 的分配和您的结构不适合您想做的事情。

你的结构应该是这样的：

type mystruct struct {
    peoples []struct {
        craft string `json:"craft"`
        name string `json:"name"`
    } `json:"people"`
}

这将为您提供一系列人员 (peoples)

    for _, eachOne := range peopleStruct.Peoples {
       fmt.Println(eachOne.Name) //eachOne.Name == name of you guys
       fmt.Println(eachOne.Craft) //eachOne.Craft == craft of you guys
    }

对于安德烈：fmt.println(peoplestruct.peoples[1].name)

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