5的平方为何是7？Go语言真相揭秘

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In Go, `5 ^ 2` evaluates to `7` because the `^` symbol does **not** mean exponentiation—it’s the **bitwise XOR operator**. This is a common source of confusion for developers coming from languages like Python (`**`) or JavaScript (where `^` *also* means XOR, but beginners often assume it’s power). Let’s break it down:

Binary representation:

• 5 in binary is 101
• 2 in binary is 010 (aligned to same bit width)

XOR compares each bit: result is 1 only when bits differ:

  101  (5)
^ 010  (2)
-----
  111  (7)

So 5 ^ 2 == 7 is mathematically correct under bitwise logic.

⚠️ Important notes:

• Go has no built-in exponentiation operator. To compute powers like 5², use math.Pow(5, 2) (returns float64) or implement integer exponentiation manually.
• ^ is also used for bitwise complement when unary (e.g., ^x flips all bits of x), but as a binary operator, it’s always XOR.
• Always double-check operator precedence: ^ has lower precedence than +/- but higher than ==, so 5 ^ 2 == 7 is parsed as (5 ^ 2) == 7 — which safely evaluates to true.

✅ Pro tip: Use fmt.Printf("%b", 5^2) to verify bitwise results during debugging.

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