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SQL数据库十四种案例介绍

来源：脚本之家 2023-01-08 10:17:20 0浏览收藏

在数据库实战开发的过程中，我们经常会遇到一些这样那样的问题，然后要卡好半天，等问题解决了才发现原来一些细节知识点还是没有掌握好。今天golang学习网就整理分享《SQL数据库十四种案例介绍》，聊聊sql案例，希望可以帮助到正在努力赚钱的你。

数据表

/*
Navicat SQLite Data Transfer

Source Server         : school
Source Server Version : 30808
Source Host           : :0

Target Server Type    : SQLite
Target Server Version : 30808
File Encoding         : 65001

Date: 2021-12-23 16:06:04
*/

PRAGMA foreign_keys = OFF;

-- ----------------------------
-- Table structure for Course
-- ----------------------------
DROP TABLE IF EXISTS "main"."Course";
CREATE TABLE Course(
    courseid integer  primary key autoincrement,
    courseme varchar(32),
    teacherid int
);

-- ----------------------------
-- Records of Course
-- ----------------------------
INSERT INTO "main"."Course" VALUES (3001, '语文', 1001);
INSERT INTO "main"."Course" VALUES (3002, '数学', 1002);

-- ----------------------------
-- Table structure for Mark
-- ----------------------------
DROP TABLE IF EXISTS "main"."Mark";
CREATE TABLE Mark(
    userid integer,
    courseid integer not null,
    score int default 0
);

-- ----------------------------
-- Records of Mark
-- ----------------------------
INSERT INTO "main"."Mark" VALUES (2001, 3001, 89);
INSERT INTO "main"."Mark" VALUES (2001, 3002, 90);
INSERT INTO "main"."Mark" VALUES (2002, 3001, 66);
INSERT INTO "main"."Mark" VALUES (2003, 3002, 85);

-- ----------------------------
-- Table structure for sqlite_sequence
-- ----------------------------
DROP TABLE IF EXISTS "main"."sqlite_sequence";
CREATE TABLE sqlite_sequence(name,seq);

-- ----------------------------
-- Records of sqlite_sequence
-- ----------------------------
INSERT INTO "main"."sqlite_sequence" VALUES ('Teacher', 1002);
INSERT INTO "main"."sqlite_sequence" VALUES ('Student', 2002);
INSERT INTO "main"."sqlite_sequence" VALUES ('Course', 3002);

-- ----------------------------
-- Table structure for Student
-- ----------------------------
DROP TABLE IF EXISTS "main"."Student";
CREATE TABLE Student(
    userid integer  primary key autoincrement,
    username varchar(32),
    userage int,
    usersex varchar(32)
);

-- ----------------------------
-- Records of Student
-- ----------------------------
INSERT INTO "main"."Student" VALUES (2001, '小明', 18, '男');
INSERT INTO "main"."Student" VALUES (2002, '小红', 18, '女');

-- ----------------------------
-- Table structure for Teacher
-- ----------------------------
DROP TABLE IF EXISTS "main"."Teacher";
CREATE TABLE Teacher(
    teacherid integer primary key autoincrement,
    teachername varchar(32)
);

-- ----------------------------
-- Records of Teacher
-- ----------------------------
INSERT INTO "main"."Teacher" VALUES (1001, '张三');
INSERT INTO "main"."Teacher" VALUES (1002, '李四');

问题：

1、查询“语文”课程比“数学”课程成绩低的所有学生的学号

select a.userid from 
(select userid,score from Mark where courseid ='3001')a,
(select userid,score from Mark where courseid ='3002')b 
where a.userid = b.userid and a.score2、查询平均成绩大于60分的同学的学号和平均成绩

select userid,avg(score) from Mark
group by userid 
having avg(score)>60;


3、查询所有同学的学号、姓名、选课数、总成绩

select s.userid ,s.username ,count_courseid as 选课数, 
sum_score  as 总成绩
from Student s
left join 
(select userid,count(courseid ) as count_courseid,sum(score) as sum_score 
from Mark group by userid  )sc
on s.userid = sc.userid;


4、查询姓‘李'的老师的个数：

select count(teachername )
from Teacher 
where teachername  like '张%';


5、检索语文课程分数小于60，按分数降序排列的同学学号：

select userid ,score
from Mark
where courseid ='3001'
and score

6、查询学/没学过”张三”老师讲授的任一门课程的学生姓名

select username  
from Student 
where userid  in (
    select userid  
    from Mark,Course,Teacher 
    where Course.teacherid  = Teacher.teacherid  and Mark.courseid = Course.courseid
    and Teacher.teachername ='张三'
);


7、查询全部学生选修的课程和课程号和课程名：

select courseid ,courseme 
from Course 
where courseid  in (select courseid from Mark group by courseid);


8、检索选修两门课程的学生学号：

select userid 
from Mark
group by userid 
having count(8) == 2;


9、查询各个课程及相应的选修人数

select courseid ,count(*) from Course group by courseid ;


10、查询选修“张三”老师所授课程的学生中，成绩最高的学生姓名及其成绩

select Student.username ,Mark.score
from Mark 
left join Student  on Mark.userid = Student.userid 
left join Course  on Mark.courseid = Course.courseid 
left join Teacher  on Course.teacherid  = Teacher.teacherid 
where Teacher.teachername  = '张三'
and Mark.score = (
select max(score) 
from Mark sc_1 
where Mark.courseid = sc_1.courseid);


11、求选了课程的学生人数：

select count(2) from 
(select distinct userid from Mark)a;


12、查询课程编号为“语文”且课程成绩在80分以上的学生的学号和姓名

select Mark.userid,Student.username  
from Mark 
left join Student on Mark.userid  = Student.userid 
where Mark.courseid  = '3001' and Mark.score>80;


13、查询每门课程的平均成绩，结果按平均成绩升序排序，平均成绩相同时，按课程号降序排列

select courseid ,avg(score)
from Mark 
group by courseid 
order by avg(score),courseid desc;


14、查询课程名称为“数学”，且分数高于85的学生名字和分数：

select c.courseme ,Student.userid ,Student.username ,Mark.score
from Course c
left join Mark on Mark.courseid  = c.courseid 
LEFT JOIN Student  on Student.userid  = Mark.userid 
where c.courseme = '数学' and Mark.score>85;


今天关于《SQL数据库十四种案例介绍》的内容就介绍到这里了，是不是学起来一目了然！想要了解更多关于mysql的内容请关注golang学习网公众号！